A takes 8 days to complete a job B TAKES 10 DAYS TO DO THE SAME JOB ,after A worked for two days B joins him.how many days will they take to complete the job
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Work done in 1 day = 1/8
so ....................2 day =1/8 ×2 =1/4
Now both worked together
1/8 + 1/10= 9/40 in 1 day
to do complete they takes 40/9 days
A & B work 9/40 work in 1 day
so days they have to work for doing 1/4 work are 40/9 ×1/4 = 10/9
They will take
![1 \frac{1}{9} \: days 1 \frac{1}{9} \: days](https://tex.z-dn.net/?f=1+%5Cfrac%7B1%7D%7B9%7D++%5C%3A+days)
so ....................2 day =1/8 ×2 =1/4
Now both worked together
1/8 + 1/10= 9/40 in 1 day
to do complete they takes 40/9 days
A & B work 9/40 work in 1 day
so days they have to work for doing 1/4 work are 40/9 ×1/4 = 10/9
They will take
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Answer:
A takes 8 days to finish a piece of work. B takes 10 days to finish the same work. How long will it take to finish the work when both of them are working together? *
18 days
2 days
9 days
40/9 days
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