Math, asked by radha5266, 11 months ago

A takes 8 more days than B to finish a work. A and B start this work and B leaves the work 9 days before the work is finished if A complete 75%of the work. how long would. A have taken to finish the work alone.​

Answers

Answered by HeAvEnPrlnCesS
0

A & B together can complete work in (25x20)/(25+20) =500/45 = 100/9 days.

They complete 5 x 9/100= 9/20 work in 5 days.

Remaining 11/20 work done by B in 11/20 x 20 = 11 days.

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