Question

A takes 9 days more than B to do a certain piece of work together they can do the work in 6 days how many days will a alone take to do the work

Answer 1

I hope that help you

Answer 2

 A can complete work alone in 18 days

Step-by-step explanation:

Let B can do work alone in x days

B's 1 day work =$\frac{1}{x}$

A takes 9 days more than B

So, A can complete in days = x+9

A's 1 day work = $\frac{1}{x+9}$

(A+B)'s 1 day work = $\frac{1}{x}+\frac{1}{x+9}$

Together they can do the work in 6 days

(A+B)'s 1 day work =$\frac{1}{6}$

So,$\frac{1}{x}+\frac{1}{x+9}= \frac{1}{6}\\6(2x+9)=(x)(x+9)\\12x+54=x^2+9x\\x^2-3x-54=0\\(x+6)(x-9)=0$

So, x=-6, 9

No. of days cannot be negative

A can do work alone = x+9 =9+9 = 18 days

Hence  A can complete work alone in 18 days

#Learn more:

A and B can complete the work in 21 days. A alone

can do the work in 15 days . In how many days can

B alone complete the work?​

https://brainly.in/question/13881902