Question

A takes as much time as B and C together take to complete the work. A and B together complete a work in 10 days while C alone can complete same work in 15 days. In how many days B alone complete work?​

Answer 1

Answer:

let’s say that :

a is the quantity per day that A produces.

b is the quantity per day that B produces

c is the quantity per day that C produces

W is the total quantity required to finish the job

then we know that :

a = b + c

10a + 10b = W

15c = W

we can rewrite this as :

10a + 10b = 15c

or:

2a + 2b = 3c

2(b + c) +2b = 3c

2b + 2c +2b = 3c

4b + 2c = 3c

4b = 3c - 2c

4b = c

meaning, 1 day of work by C equals 4 days of work by B

in other words, C is 4 times as productive as B

therefore, if C needs 15 days to finish the job, B will need 60 days to finish the same job.

The question was not asked, but A needs only 12 days to finish the job.

Step-by-step explanation:

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