Question

A takes Rs. 3,000 from B for 2 years at the rate of 10% half early simple interest. What amount will be paid by A to B after end of 2 years?​

Answer 1

Given:-

P=Rs.3000

R=10%

T=2 years

To Find:-

Amount after the 2 year interval.

Answer:-

Interest (I)=$\frac{P*R*T}{100}$

$\frac{3000*10*2}{100} \\\\=\frac{3000*20}{100} \\\\=\frac{30*20}{1} \\=600$

Amount=Principal +Interest

=3000+600

=Rs.3600

Formulas to remember:-

Simple Interest = Principle × Rate × Time = PTR/100

C.I. = Principal (1 + Rate)Time − Principal/100

Answer 2

Given :-

• P = Rs. 3,000
• R = 10%
• T = 2 years

To find :-

• Amount after the 2 year interval.

Solution :-

Interest (I) = ${\sf{\frac{P \: \times \: R \: \times \: T}{100}}}$

${\sf{\frac{3000 \: \times \: 10 \: \times 2}{100}}}$

${\sf{= \frac{3000 \: \times \: 20}{100}}}$

${\sf{~~~~~= \frac{300 \: \times \: 20 }{1} }}$

${\sf{~~~~~~~~= \frac{1}{600} }}$

Amount = Principal + Interest

= 3000 + 600

= Rs. 3600

Formulas to remember :

Simple Interest = Principal × Rate × Time = ${\sf{ \frac{P \: \times \: R \: \times \: T}{100}}}$

C.l = Principal (1 + Rate)Time - ${\sf{\frac{Principal}{100} }}$