a takes six times as long a and b can do a work in 12 days, b and c in 15 days, c and a in 20 days. if a, b and c work together, they will complete the work in: a.5 daysto do a piece of work as b takes. a and b together can do a piece of work in 4 days.
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A and B can finish a work together in 12 days, and B and C together in 16 days. If A alone works for 5 days and then B alone continues for 7 days, then remaining work is done by C in 13 days. In how many days can C alone finish the complete work?
Originally Answered: A+B can do a work in 12 days. B+C can do the same work in 16 days. A started the work for 5 days, then B takes over the work and worked for 7 days. C completed the remaining work in 13 days. In how many days can C alone complete the whole work?
Total work = 48 unit
efficiency of a+b =4 ————-(1)
efficiency of b+c =3 ————-(2)
According to question
5a +7b +13c = 48
now using 1 and 2 equation
5a+ 7(4-a) +13(a-1) =48
11a =33
a=3 , b =1 , c = 2
Time taken by C = 48/2 =24 days
Hey dude this is similar example for your question. Hope this will help you... ✌
Originally Answered: A+B can do a work in 12 days. B+C can do the same work in 16 days. A started the work for 5 days, then B takes over the work and worked for 7 days. C completed the remaining work in 13 days. In how many days can C alone complete the whole work?
Total work = 48 unit
efficiency of a+b =4 ————-(1)
efficiency of b+c =3 ————-(2)
According to question
5a +7b +13c = 48
now using 1 and 2 equation
5a+ 7(4-a) +13(a-1) =48
11a =33
a=3 , b =1 , c = 2
Time taken by C = 48/2 =24 days
Hey dude this is similar example for your question. Hope this will help you... ✌
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