Question

A takes twice as much a time as b and c takes thrice as much time as b to finish a work working together they can finish the work in 12 days find the number of days a needed for a to do the work alone

Answer 1

Answer:

Now, A+B+C one-day work =6 units. Since they complete the work in 2 days, so total work will be 2×6=12 units. B alone will take 122 i.e. 6 days.