A takes twice as much as B and thrice as much as C to finish a work; working together they can finish the work in 10 days. Find the time each will take to finish the work separately.
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The working capacity of B = 2 times the working capacity of A
B = 2 A
The working capacity of C= 2 times the working capacity of A
C = 3 A
Now, A + B+ C can finish 1 work 10 days
A + 2A+ 3A can finish 1 work 10 days
6 A can finish 1 work in 10 days
A cando 1work in 60 days
B can do 1 work in 12
time taken by A = 12*60 = 30 days
C can do 1 work in13timetakenbyA=13∗60=20days ANS
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