Question

A tall rectangular vessel is half filled with water the dimension of its base are 50 cm and 30 cm A heavy cube of edge 10cm is dropped into The vessel find the rise in the water level in the vessel​

Answer 1

The rise in the water=1000cm^31000cm

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Step-by-step explanation:

Dimension of base of rectangular vessel=50 cm\times 30cm50cm×30cm

Side of heavy metal cube =10 cm

We know that

Volume of cube=(side)^3(side)

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Using the formula

Volume of heavy metal cube=(10)^3cm^3(10)

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cm

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Volume of heavy metal cube=10\times 10\times 10 cm^310×10×10cm

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By using 10^3=10\times 10\times 1010

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=10×10×10

Volume of heavy metal cube=1000cm^31000cm

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Volume of heavy metal cube=Level of water rises=1000cm^31000cm

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Answer 2

Hope it will be helpful to u