Question

\.A tall, yellow-seeded pea plant heterozygous for height and seed
color (TtYy) is crossed with a tall, green-seeded pea plant that is
heterozygous for height but homozygous recessive for seed colour
(Ttyy). If 80 offspring are produced, how many are expected to be
tall and have yellow seeds?

Answer 1

22 seeds are expected to be tall having yellow seeds.

Explanation:

• Let's draw a punnet square to draw the results:

           TY          Ty                tY              Ty

Ty    TTYy         TTyy         TtYy            TTyy

Ty    TTYy         TTyy         TtYy             TTyy

ty      TtYy          Ttyy          ttYy            Ttyy

ty      TtYy          Ttyy          ttYy             Ttyy

• From the punnet square, we can see that the ration of tall and yellow seeds is 6:16 which is equal to 3:8
• As the question above tells, the total number of seeds is 80.
• So, 3x+8x= 80
• Hence, 11x=80
• x= 80/11
• 7.2
• Now, as we expect the tall and yellow seeds to be 3 so, 3x
• 3(7.2)
• 21.6
• Hence, the number of tall and yellow seeds will be 22.

Answer 2

Answer:

22 seeds are expected to be tall having yellow seeds.

Explanation:

Let's draw a punnet square to draw the results:

           TY          Ty                tY              Ty

Ty    TTYy         TTyy         TtYy            TTyy

Ty    TTYy         TTyy         TtYy             TTyy

ty      TtYy          Ttyy          ttYy            Ttyy

ty      TtYy          Ttyy          ttYy             Ttyy

From the punnet square, we can see that the ration of tall and yellow seeds is 6:16 which is equal to 3:8

As the question above tells, the total number of seeds is 80.

So, 3x+8x= 80

Hence, 11x=80

x= 80/11

7.2

Now, as we expect the tall and yellow seeds to be 3 so, 3x

3(7.2)

21.6

Hence, the number of tall and yellow seeds will be 22.

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