A tangent AB at a point A of a circle of radius
5 cm meets a
line through the centre at O at a
point B so that
OB = 13 cm. find length of AB.
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Answers
Answered by
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Step-by-step explanation:
In figure, AB is the tangent of circle (O,r).
Here r = 5 cm. = AO and OB = 12 cm.
Since tangent is perpendicular to radius OA, therefore OAB is a right triangle.
Now in rt Δ OAB, ∠A=90
∘
Thus OB
2
=OA
2
+AB
2
⇒12
2
=5
2
+AB
2
⇒AB
2
=144−25=119
Therefore, AB=
119
cm
solution
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