Question

a tangent AB touches the circle with centre O, at the point O, if the radius of the circle is 5 cm, OB=10cm and OB =AB then fins AP.​

Answer 1

Answer:

figure, AB is the tangent of circle (O,r).

Here r = 5 cm. = AO and OB = 12 cm.

Since tangent is perpendicular to radius OA, therefore OAB is a right triangle.

Now in rt Δ OAB, ∠A=90∘

Thus OB2=OA2+AB2

⇒122=52+AB2

⇒AB2=144−25=119

Therefore, AB=119 cm



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Answer 2

Answer:

AB=119 cm

Given:

radius of the circle is 5 cm

OB=10cm and OB =AB

To find:

tangent AB

Explanation:

figure, AB is a tangent of circle (O,r).

Here r = 5 cm. = AO and OB = 12 cm.

Since tangent is perpendicular to radius OA, therefore OAB is a right triangle.

Now in rt Δ OAB, ∠A=90∘

Thus OB2=OA2+AB2

⇒122=52+AB2

⇒AB2=144−25=119

Therefore, AB=119 cm

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