A tangent galvanometer has a coil with 50 turns
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Explanation:
Given A tangent galvanometer has a coil with 50 turns and radius equal to 4 cm. A current of 0.1 A is passing through it. The plane of the coil is set parallel to earth’s magnetic meridian. If the value of earth’s horizontal component of magnetic field is 7 x 10^5 tesla and μo = 4π x 10^-7 W / amp x m then the deflection in the galvanometer needle will be
- In a tangent galvanometer current I = 2 r B tan theta / μo n (in horizontal direction)
- So tan theta = I μo n / 2 R B
- = 0.1 x 4 π x 10 ^-7 x 50 / 2 x 4 x 10^-2 x 7 x 10^-5
- = 1.12
- So tan theta = 1.12
- Or theta = tan^-1 1.12
- Or theta = 48.2 degree
Reference link will be
https://brainly.in/question/2557428
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