A tangent is drawn from the origin to the circle x^2+y^2+2x+2y+1=0. What is the point of contact?
(a) (-1,-1)
(b) (0,-1)
(C) (0,1)
(d) (1,1)
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Answer:
(-1,-1)
x^2+y^+२x+२y+1=0 compare with x^2+y^2+२gx+२fy+c=0
then we find
g=1 f=1
the point of contact is (-g, -f)
so ans is (-1,-1)
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