A tangent of length 12 cm is drawn to a circle of radius 5 cm from a point P away from the center. Find the distance of P from the center
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Answered by
9
A right angled triangle is formed so 12^2+5^2=169
root over 169=13
therefore the distance from o to centre is 13cm
root over 169=13
therefore the distance from o to centre is 13cm
Answered by
13
Point P is 13 cm away from the centre...
Here's the reason why..
Since tangent to a circle are perpendicular to the radius through the point of contact....therefore in ΔOAB ,∠OAB=90°
Now on applying Pythagoras theorm,
AB² =OB² + OA²
Therefore AB²= 12²+5²
Ab²=144+25
AB²=169
Ab²=13²
Hence AB=13 cm
Hope it helps....!
Here's the reason why..
Since tangent to a circle are perpendicular to the radius through the point of contact....therefore in ΔOAB ,∠OAB=90°
Now on applying Pythagoras theorm,
AB² =OB² + OA²
Therefore AB²= 12²+5²
Ab²=144+25
AB²=169
Ab²=13²
Hence AB=13 cm
Hope it helps....!
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