Question

A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that PQ=12 cm. Fin length of OQ​

Answer 1

Correct Question: A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that PQ=12 cm. Find length of PQ​

Answer:

PQ = √119 cm

Step-by-step explanation:

The line drawn from the centre of the circle to the tangent is perpendicular to the tangent.

∴ OP ⊥ PQ

By Pythagoras theorem in ΔOPQ,

OQ2 = OP2 + PQ2

⇒ (12)2 = 52 + PQ2

⇒PQ2 = 144 - 25

⇒PQ2 = 119

⇒PQ = √119 cm

Hope it helps you !!!

Answer 2

Answer:

OQ=13

Step-by-step explanation:

always a radius of a circle is perpendicular on his tangent at point where tangent touch to circle, then ,

∆OPQ is a Right angle ∆,& angle OPQ=90°& OQ is haypotanious

then,

OQ square =OP square+ PQ sq.

,OQ sq.=(5×5)+(12×12)

OQ=√(25+144)

OQ=√169

OQ=13