A tangent PQ at a point P of a circle of
radius 5 cm meets a line through
the centre 0 at a point Q so that
OQ = 12 cm. Find length of PQ.
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O is the center of the circle. Thus OP = 5 cm, which is the radius of the circle, and OQ = 12 cm. ... The tangent at any point of circle is perpendicular to the radius through the point of contact. ∴∠OPQ=90∘.
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Answer:
PQO is a right-angled triangle
in that OQ is a hypotenuses = 12 cm
PO is a side of that triangle = 5 cm
PQ = √QO²+ PO²
∴Pytogerous Theorem
PQ= √12²+5²
√169 = PQ
PQ = 13cm
∴length of PQ = 13cm
∴13, 12, 5 are pythogeren triplets
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