Question

a tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q such that PQ is equals to 12 CM length of PQ is​

Answer 1

Can't understand ur question... Plzz clear it out....

Answer 2

Given :PT & QT are tangents

OP=OQ = 5cm

PQ =12cm

PR = RQ = 6cm

Construction : Jion PQ

Proof : In triangle OPR

OP^2 = PR^2 + RO^2

5^2 = 6^2 + RO^2

25 =36 + RO^2

RO^2 = 11

RO = ROOT 11

IN TRIANGLE (OPT)

PR^2 = OR - RT

12 = ROOT 11 - RT

RT = 12 ROOT 11

IN TRIANGLE (PRT )

PT^2 = PR^2 +RT^2

PT^2 = 6 ^2 + 12 ROOT 11

$48 \sqrt{11}$