Question

A tangent PQ at a point P of a circle of radius 5cm meets a line segment through centre O at a point Q such as OQ=12cm.find pq ​

Answer 1

Answer:

In the above circle, O is the centre.

PQ is a tangent at point P.

OQ is radius of circle. Therefore, length of OQ= 5 cm (given)

In right triangle OPQ

OQ^2=OP^2+PQ^2 (By phythagoras theorem)

13^2=5^2+PQ^2

169=25+PQ^2

PQ^2=169-25

PQ^2=144

PQ= Square root of 144= 12 cm

Answer 2

Step-by-step explanation:

make a figure of this

you will understand this question

easily by yourself