Question

a tangent PQ at point P of a circle of radius 5cm meets a line through the centre O at a point Q so that OQ is 13cm. find length of PQ

Answer 1

given oq=13cm
and radius of circle = 5 cm
 now,

joint point o and p
now triangle POQ is and right angle triangle as tangents are perpendicular to center.

now use Pythagoras theorem to solve it.
the answer come up with 12 cm.
 

Answer 2

Answer:

Step-by-step explanation:

In the above circle, O is the centre.

PQ is a tangent at point P.

OQ is radius of circle. Therefore, length of OQ= 5 cm (given)

In right triangle OPQ

OQ^2=OP^2+PQ^2 (By phythagoras theorem)

13^2=5^2+PQ^2

169=25+PQ^2

PQ^2=169-25

PQ^2=144

PQ= Square root of 144= 12 cm