Question

a tangent PQ at point P of a circle of radius 5cm meets a line through the centre O at a point Q so that OQ is 13cm .find length of PQ

Answer 1

In the above circle, O is the centre.
PQ is a tangent at point P.
OQ is radius of circle. Therefore, length of OQ= 5 cm (given)
In right triangle OPQ
OQ^2=OP^2+PQ^2 (By phythagoras theorem)
13^2=5^2+PQ^2
169=25+PQ^2
PQ^2=169-25
PQ^2=144
PQ= Square root of 144= 12 cm

Answer 2

Answer:

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