Question

A TANGENT PT IS DRAWN PARALLEL TO CHORD AB OF A CIRCLE . PROVE THAT APB IS AN ISOSCELES TRIANGLE

Answer 1

Join PO and produce to D  

Now OP _|_ TP 

TP 

AB 

∠ADP = 90° 

Hence, PD is a bisector of AB 

= ΔADP 

ΔBDP 

Thus, APB is an isosceles trianlge

Answer 2

There are actually two different ways of doing this question, there are both the ways in the attachment.