A tangent PT touches a circle of radius 6cm at point T. If OP is 8 cm Find PT.
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Let O be the centre of the given circle and let P be a point such that OP = 10 cm.
Let PT be the tangent such that PT = 8 cm.
Join OT.
Now, PT is a tangent at T and OT is the radius through T.
Therefore, OT⊥PT.
Using pythagoras theorem in △OTP, we have,
OP
2
=OT
2
+PT
2
OT
2
=100−64=36
OT=6 cm
Therefore, the radius of the circle is 6 cm.
Step-by-step explanation:
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