a tangent to a circle at the point p from a is 24 cm long if o is the centre of the circle OA = 26 cm find the diameter of the circle
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[ figure is in the attachment]
now,
PA = 24CM , OA = 26CM.
IN ∆ APO , <P = 90°
so, by Pythagoras theorem
OA² = PO² + PA²
(26)² = PO² + (24)²
(26)² - (24)² = PO²
PO² = (26 - 24)(26 + 24)
PO² = 2(50)
PO² = 100
PO = 10cm
HENCE, diameter of circle = 2×PO
so, diameter = 2×10cm = 20cm.
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