A tangent to a circle at the point P from A is 24cm long. If O is the centre of the circle and OA=26cm. find the diameter of the circle.
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we know that ,
op is perpendicular to oa
that is angle OPA is equal to 90 degrees
by using Pythagoras theorem
OA^2=OP^2+PA^2
26^2=op^2+24^2
OP=root of 26^-24^2
OP=root of676-576
OP=root of 100
=10
:radius=10
diameter= 2r=2(10)
=20cm
op is perpendicular to oa
that is angle OPA is equal to 90 degrees
by using Pythagoras theorem
OA^2=OP^2+PA^2
26^2=op^2+24^2
OP=root of 26^-24^2
OP=root of676-576
OP=root of 100
=10
:radius=10
diameter= 2r=2(10)
=20cm
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