Question

A tangential force of 2700 N is acting on a shaft of diameter 20 mm. Find the work done by the force for one revolution of shaft.​

Answer 1

The work done by the tangential force is equal to zero.

Explanation:

• this is because the work done is the product between the force applied and the displacement that is done by the object.
• after one revolution of the shaft there is no displacement of the wheel as a whole. Hence there is no change in the displacement and hence the work done is equal to zero. even though the distance covered by the wheel is equal to the circumference of the wheel but the work done is zero because displacement is zero

Answer 2

Answer:

Work Done = 169.64 Nm

Explanation:

F = 2700 N,

D = 20mm = $\frac{20}{1000}$ m = 0.02 m

R = $\frac{D}{2}$ = $\frac{0.02}{2}$ = 0.01 m

∅ = 2π  → (Angle turned for one revolution )

⇒ Torque = F X R

                 = 2700 X 0.01

                 = 27 Nm

now,

   Work done = T X ∅

                       = 27 X 2π

                       = 169.64  Nm