Question

A tank 15m long 10m wide and 6m deep is open at the top. If the width of the sheet is 2m,then the cost of iron sheet at the rate of Rs5 per metre is

Answer 1

Hello Mate!

So a tank which is opened at top = Lateral surface area + base area

Lateral surface area = 2h( l + b ) and base area = lb

= 2(6)[ 15 + 10 ] m² + (15)(10) m²

= [ 12 × 25 + 150 ] m²

= 450 m²

Now, let a sheet cover such area of cuboid.

Length of sheet × breadth of sheet = Area covered

Length × 2 m = 450 m²

Length = 450/2 or 225 m

Hence, cost of iron sheet = 225 × Rs. 5

= Rs 1125

Merry Xmas

Have great future ahead!

Answer 2

As tank is open at the top

So Surface area becomes 2( lb+bh+hl) - lb

= 2( bh+ hl) + lb

= 2h( b+l) + lb
= 2× 6( 10 +15) + 15× 10

= 12( 25) + 150

= 300 +150

= 450 M^2

As width of sheet is 2m
let length be l

So 2l = 450

l = 450/2 = 225

As cost is 5rs per m

so 225 m cost is 225× 5= 1125 rs


✌✌✌Dr.Dhruv✌✌✌✌