Question

A tank 2m high is half filled with water and then filled to the top with oil of density 0.8g/cc . What is the pressure at the bottom of tank due to these liquids

Answer 1

the part of tank filled with water

=(2÷2)m=1m=100cm

pressure on the tank =(100×1×980)dyne/ cm^2

=98000 dyne/cm^2

pressure on the tank by oil=

(100×0.8×980)dyne/cm^2

=78400dyne/cm^2

total pressure on tank =176400 dyne/ cm^2

Answer 2

Answer:

Explanation:

Solution :-

Given :-

h = 2 m

Density of oil, ρ(o) = 0.80 g/cc

= 0.80 × 10³ kg/m³

Density of water, ρ(w) = 10³ kg/m³

Mean density, say ρ = ρ(o) + ρ(w)/2

= 0.80 × 10³ + 1 × 10³/2

= 0.90 × 10³ kg/m³

Therefore, Pressure at the bottom,

P = hρg

P = 2 × 0.90 × 10³ × 10

P = 1.80 × 10⁴ Nm⁻²

Hence, the pressure at the bottom of tank due to these liquids is 1.80 × 10⁴ Nm⁻².