Question

A tank 6 m long and 4 m wide contains water up to a depth to 1 m. The total area of the wet surface is:

Answer 1

Answer:

Step-by-step explanation:

length = 6m

breadth = 4m

height = 1m

volume = l × b × h

= 6 × 4 × 1 = 24 m^3

area of wet surface = area of cuboid containing water

= 2 ( bh + hl ) + lb

= 2 (4×1 + 1×6) + 6×4

=2 (4 + 6) + 24

= 2 (10) + 24

= 20 + 24

= 44 m^2

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