Question

A tank can be filled by 2 pipes A and B in 8 hours and 12 hours, respectively. The full tank can be emptied by a third pipe in 24 hours. If all the three pipes are open at the same time, in how many time will the empty tank be filled?​

Answer 1

Answer:

6 hours

Step-by-step explanation:

Amount of water pipe A can fill each hour (in comparison to the tank)=$\frac{1}{8}$

Amount of water pipe B can fill each hour (in comparison to the tank)=$\frac{1}{12}$

Amount of water third pipe can drain each hour (in comparison to the tank)=$\frac{1}{24}$

Time it take for the tank to be filled=1÷($\frac{1}{8}$+$\frac{1}{12}$-$\frac{1}{24}$)

                                                          =6

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