Question

A TANK CAN BE FILLED BY ONE PIPE IN X MINUTE AND EMPTIED BY ANOTHER PIPE IN (X+5) MINUTES . BOTH THE PIPES WHEN OPENED TOGETHER CAN FILL TANK IN 16.8 MINUTES . FIND THE X.

Answer 1

i am giving you hint how to solve .
1/x+1 (x+5)=1/16.8
solve this and you will get a quadratic equation.then find out the solutions for that equation and ine of them is your answer.
if any query is there ask again

Answer 2

Given that,

One pipe can fill the tank in ‘x’min&other can empty it in (x+5)min

Let the volume of tank be’ V’.

•Therefore,Volume of water filled by one pipe in x min=V

•Volume of water filled by pipe in 1 min=V/x

Also,

•Volume of outflow of water by another pipe in (x+5)min=V

•Volume of outflow of water by another pipe in 1 min=V/(x+5).

•Volume of water filled in tank for 1 min=

(V/x)-(V/x+5).

Also given,both together can fill the empty tank in 16.8min.

SEE ABOVE ☝☝☝ FOR FURTHER CALCULATIONS!!!


On solving above equation,we get x=7


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