A tank can be filled by taps A and B in 10 minutes and 15 minutes respectively. A third tap C can empty the tank completely in 8 min . If all the taps are open how much time will it take to fill it
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(A+B)'s filling (2+1)=3 units/min
In 5 minutes.they will fill 3×5=15units
Remaining capacity =60−15=45 units
second pipe (B) fills it in R.Cefficiency of B=451=45 minutes
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