Math, asked by seema23466, 1 year ago

A tank can be filled by two taps A and B in 8 hours and 10 hours respectively. The full tank can be emptied by a third tap C in 9 hours. If all the taps are turned on at the same time, in how much time will the empty tank be filled up completely?

Answers

Answered by sonabrainly
12

Answer:

Step-by-step explanation:

Tap A can fill tank in 12 hrs

Tap B can fill tank in 16 hrs

Tap C can empty the tank in -8hrs

Tap A's 1 hr work = 1/12

Tap B's 1 hr work = 1/16

Tap C's 1 hr work = -1/8

Tap (A+B+C)'s 1 hr work = 1/12 + 1/16 - 1/8

= 7-6/48 = 1/48 = 48 hours

Hence, all the taps will take 48 hrs to fill the tank.

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