A tank can be filled by two taps A and B in 8 hours and 10 hours respectively. The full tank can be emptied by a third tap C in 9 hours. If all the taps are turned on at the same time, in how much time will the empty tank be filled up completely?
Answers
Answer:
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Step-by-step explanation:
Time taken by tap A to fill the tank = 8 hours.
Time taken by tap B to fill the tank = 10 hours.
Time taken by tap C to empty the full tank = 9 hours.
A’s 1 hour’s work = ¹/₈
B’s 1 hour’s work = ¹/₁₀
C’s 1 hour’s work = −19 (cistern being emptied by C)
Therefore, (A + B + C)’s 1 hours net work= (¹/₈ + ¹/₁₀ - ¹/₉) = (45 + 36 – 40)/360 = ⁴¹/₃₆₀
Thus, tank will be filled completely in 36041 hours, when all the three are opened together.
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Answer:
Step-by-step explanation:
tap A to fill the tank = 8 hours.
B to fill the tank = 10 hours.
C to empty the full tank = 9 hours.
A’s 1 hour’s work = ¹/₈
B’s 1 hour’s work = ¹/₁₀
C’s 1 hour’s work = −19 (cistern being emptied by C)
(A + B + C)’s 1 hours net work= (¹/₈ + ¹/₁₀ - ¹/₉) = (45 + 36 – 40)/360 = ⁴¹/₃₆₀