A tank can be filled by two taps A and B in 8 hours and 6 hours, respectively. The full tank can be emptied by a third tap C in 4 hours . If all the taps are turned on at the same time in how much time will the empty tank be filled up completely?
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Answered by
0
Answer:
find the lcm of 8 ,6 and 4
divide the lcm by 60 as
1 hr=60 mins
Answered by
4
Answer:
Tap A fills the tank in = 8 hours
Tap A fills in 1 hour = 1/8 tank ...(i)
Tap B fills the tank in = 6 hours
Tap B fills in 1 hour = 1/6 tank ...(ii)
Tap C empties the tank in = 4 hours
Tap C empties in 1 hour = 1/4 tank ...(iii)
From (i), (ii) and (iii), we get
∴ (A + B + C )'s fill in 1 hour = (1/8 + 1/6 - 1/4) tank = 3+4-6/24 = 1/24
∴ (A + B +c) fill the tank in = 24 hours.
Step-by-step explanation:
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