Question

A tank can be filled by two taps A and B in 8 hours and 6 hours respectively. The full tank can be emptied

by a third tap C in 4 hours. If all the taps are turned on at the same time, in how much time will the empty

tank be filled up completely?


need a correct ans
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Answer 1

Step-by-step explanation:

Both the infilling Taps can fill the Tanks in 1 hour =(1/8+1/10) parts of the Tank

The 3rd Tap can empty in 1 hour =1/12 parts of the Tank

So volume of water remains in the Tank if all the 3 taps are on=1/8+1/10–1/12

=15/120+12/120–10/120=27/120–10/120=17/120 parts of the Tank

Time required to fill completely = 120/17=7.0588 Hours = 7 hrs 3.5 min

ok.....guri....