Question

. A tank can be filled completely by tap A
in 10 hours and by a tap B in 6 hours. How
long will it take to fill the tank, if both taps
are started at the same time?​

Answer 1

Answer:

3.75 hours.

Step-by-step explanation:

So, in order to find out the time required if both, Tap A and Tap B, to fill another similar tank, we need to consider the reciprocals of the times and add them up.

Let’s assume that the time required when both the taps are running to be “X”.

Therefore, we get

1/X = 1/10hours + 1/6hours

As a result, we get “X” as 3.75 hours.

Hope, you understood it