Math, asked by fadiljbl1212, 6 months ago

a tank cn be filled by 2 taps A and B in 12 hours and 16 hours respectively . the full tank cn be emptied by 3rd tap in 8 hours . in all taps we turn on at same time in how much time will the empty tank be filled up completely

Answers

Answered by itsbrainlybiswa
6

Answer:Tap A can fill tank in 12 hrs

Tap B can fill tank in 16 hrs

Tap C can empty the tank in -8hrs

Tap A's 1 hr work = 1/12

Tap B's 1 hr work = 1/16

Tap C's 1 hr work = -1/8

Tap (A+B+C)'s 1 hr work = 1/12 + 1/16 - 1/8

= 7-6/48 = 1/48 = 48 hours

Hence, all the taps will take 48 hrs to fill the tank.

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