A tank containing 50 litres of water develops a leak and loses water at a constant rate. After 20 minutes it contains 40 litres. After a further 30 minutes the tank is 5% of its full capacity. Determine the tank’s capacity.
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Answer:
Let the full capacity of tank be x litres
Tank contains 50L of water
After 20 mins,
Tank contains 40L of water
After a further 30 mins,
Tank contains 5/100 × x = x/20 L......(i)
So in 20 mins the tank loses (50-40)L
In 1 min= 10/20 = 1/2 L
So in 50 mins the tank loses = 1/2 ×50 = 25L
So the tank's capacity after a total of 50mins(30+20)
= 50L - 25L = 25L
ATQ,
x/20 = 25
x= 25×20 = 500L
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