Question

A TANK CONTAINS A MIXTURE OF 16 G OF HELIUM AND 40G OF CARBON DIOXIDE a. calculate the number of moles(gram-atoms) of helium and the number of moles of carbon dioxide in the tank
b. how many atoms of helium and molecules of carbon dioxide does the tank contain?

Answer 1

Answer:

this is the answer hope it helps you

Answer 2

Given: A tank contains a mixture of 16 gram of helium and 40 gram of carbon dioxide.

To find: 1-Number of moles of carbon dioxide and helium in the tank

2-Number of atoms of helium and molecules of carbon dioxide the tank contains

Explanation: Given mass of helium= 16g

Molar mass of helium= 4g

Number of moles= given mass/molar mass

= 16/4 = 4 moles

Given mass of carbon dioxide= 40 g

Molar mass of carbon dioxide= 44 g

Number of moles= Given mass/ molar mass

= 40/44= 0.91 moles

Number of atoms of helium

= moles* Avogadro no.

= 4* 6.022* 10^23

= 24.08* 10^23 atoms

Number of molecules of carbon dioxide

= moles * Avogadro no.

= 0.91* 6.022* 10^23

= 5.48* 10^23 molecules

Therefore, the number of moles of helium is 4 and the number of moles of carbon dioxide is 0.91. The number of atoms of helium is 24.08 * 10^23 and number of molecules of carbon dioxide is 5.48* 10^23.