Question

A tank fills completely in 2 hours if both the taps are open. If only on of the taps is open at a given time, , the smaller tap takes 3 hours more than the larger one to fill the tank. How much time does each tap take to fill the tank completely? NO Spam plz!

Answer 1

Answer:

small tap take 6hrs and big tap will take 3hrs

Step-by-step explanation:

let large tap fill tank =x hours

let small tap fill tank =x+3 hours

SO, 1/X + 1/X + 3=1/2

i.e (X+3+X) /X (X+3)=1/2

i.e 2 (2×+3)=×^2+3×

i.e ×^2 + 3× -4×-6=0

i.e ×^2-×-6=0

i.e (×-3) (×+2)=0

i.e large tap take 3hrs

small tap take (3+3)=6hrs