Question

a tank has 30 m long 20 m broad 12 m deep us dug in a field which is 500m long and 30m wide by how much will the level (in m) of the feilds ruse if the earth dug out is evenly spread on the re.ain part of the field​

Answer 1

Answer:

Volume of earth taken out = volume of the tank

=30m × 20m × 12m

Area of the tank =l×b

=30m × 20m

=600m²

Area of the field =500m × 30m

=15000m²

Area of the reaming field =(15000−600)m²

=14400 m²

∴ level of the filed raised

= (7200÷14400) m = (1÷2) m = 50 cm

Step-by-step explanation:

Answer 2

Answer:

Volume of earth taken out = volume of the tank

$\sf \: =30×20×12m {}^{3}$

$\sf \: Area \: of \: the \: tank \pink{ =l×b}$

$\: \sf=(30×20)m {}^{2}$

$\sf \frak\red{=600m {}^{2} }$

$\sf \: Area \: of \: the \: field\red{\: (500×30)m {}^{2}}$

$\sf \: =15000m {}^{2}$

$\sf \: Area \: of \: the \: reaming \: field =$

$\sf \: (15000−600)m {}^{2}$

$\sf \red{=14400m {}^{2} }$

∴ level of the filed raised

$\sf = \frac{7200}{14400} m \: = \frac{1}{2} m$

$\sf \: { \pink{ \frak{ \: =50cm}}}$

Hence, This is Answer.