Question

A tank has a capacity of 240 litres. A pipe
can empty 1/4th of the tank in 5 minutes and
another pipe can empty 1/3rd of the tank in 6
minutes. The tank is filled and both the pipes
are opened for 3 minutes. How much of the
water is now left in the tank?

Answer 1

Answer:

164l

Step-by-step explanation:

Water which pipe A can empty in 5 minutes=1/4*240=60l

Water which pipe A can empty in 1 minute=60l/5=12l

Water which pipe B can empty in 6 minutes=1/3*240=80l

Water which pipe B can empty in 1 minute=80l/6=40/3l

According to question,

If both pipes are opened for 3 minutes then water taken out=(12l*3)+(40/3l*3)=36l+40l=76l

Water left in tank=240l-76l=164l

Answer 2

Answer: Amount of water left in the tank = 164 litres

Step-by-step explanation:

Given : Total capacity of the tank = 240 litres

Amount the tank can empty in 5 minutes = 1/4

Amount another pipe can empty in 6 minutes

Time for which both tanks are filled and opened = 3 minutes

To find : Amount of water left in the tank

Amount of water  pipe A can empty in  span of 5 minutes = 1/4 x 240 = 60 litres

Amount of water which pipe A can empty in 1 minute = 60litres/5 = 12 litres

Amount of water pipe B can empty in 6 minutes = 1/3 x 240 = 80 litres

Amount of water  pipe B can empty in 1 minute = 80litres/6 = 40/3 litres

To find the amount of water left in tank if both pipes are opened for 3 minutes each then water taken out from the tank = (12litres x 3) +(40/3 litres x 3) = 36 litres +40 litres = 76 litres

Thus water left in tank = Total capacity of the tank - amount of water left in tank if both pipes are opened at the same time= 240 litres - 76 litres = 164 litres.

Answer = 164 litres

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