A tank has two pipes A and B. A can fill the tank with water in 8 hours and B can empty it in 12 hours. If the pipe A be opened first and the pipes be opened alternatively one at a time for 1 hour each, in how many hours will the tank be filled up?
Answers
Step-by-step explanation:
Redox is a type of chemical reaction in which the oxidation states of atoms are changed. Redox reactions are characterized by the actual or formal transfer of electrons between chemical species, most often with one species undergoing oxidation while another species undergoes reduction
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Answer:
Given:
Pipe A alone can fill the tank = 8 hrs
Pipe B alone can fill the tank = 12 hrs
Time ratio of Pipe A and B = 8 ∶ 12 = 2 ∶ 3
Concept used:
Efficiency is inversely proportional to time.
Calculation:
Efficiency ratio of pipe A and B = 3 ∶ 2
Total work = 3 × 8 = 24
Both pipes opened alternately for 1 hr
Total work in 2 hrs = 3 + 2 = 5
Work in 8 hrs = 5 × 4 = 20
Work in next 1 hr (9th) = 20 + 3 = 23
Remaining work = 24 - 23 = 1
B alone can work in 1 hr = 2
B alone can work in 1/2 hr = 1
So, the total work complete in hrs
F1 V.G Pallavi 13 Nov 2019 D7
Total work = 24
Work completed in 2 hrs = 3 + 2 = 5
Work completed in 8 hrs = 20
work completed in 9th hr = 20 + 3 = 23
B completed remaining 1 work in = 1/2 hr
Total work completed in = hrs
∴ The total work will be completed in hrs.