A tank is 45 m long, 15 m wide and 13 m deep. What is the cost of plastering its
walls and bottom at the rate of 80 paise per sq.m
Answers
Answer:
The cost of plastering the walls and bottom is 1788 Rupees
Step-by-step explanation:
Given, the dimensions of the tank:
Length = 45 m, breadth = 15 m, height = 13 m
Total surface area of walls and bottom surface = 2(bh+lh) +lb
= 2[(45×13) + (15×13)] + 45×15
= 2(585+195) + 675
= 2× 780 + 675
= 1560+675
= 2235 m²
Cost of plastering per sq.m = 80 paise
Cost of plastering 2235 m² = 80× 2235 = 178800 paise
= Rs 1788
The cost of plastering the walls and bottom is Rs 1788
The cost of plastering its walls and bottom at the rate of 80 paise per sq.m is Rs. 1788.
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Let's understand a few concepts:
To solve the given problem we will use the following formulas:
where l = length, b = breadth and h = height
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Let's solve the given problem:
The dimensions of the cuboidal tank:
Length (l) = 45 m
Breadth (b) = 15 m
Depth/Height (h) = 13 m
Finding the area of 4 walls of the tank:
∴ The area of 4 walls of the tank is,
= Area of 4 walls
=
=
=
=
Finding the area of the bottom of the tank:
∴ The area of the bottom of the tank is,
= Area of a rectangle
=
=
=
Finding the area of walls and bottom of the tank:
∴ The area of the 4 walls and the bottom of the cuboidal tank is,
= [Area of 4 walls] + [Area of the bottom]
=
=
Finding the cost of plastering the walls + bottom of the tank:
If the cost of plastering 1 m² of walls + bottom = Rs. 0.80 . . . [since 1 rupee = 100 paise ∴ 80 paise = Rs. 0.80]
Then,
The cost of plastering 2235 m² of walls + bottom at the same rate will be,
=
=
Thus, the cost of plastering the walls and bottom of the tank at the rate of 80 paise per sq. m is Rs. 1788.
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