Question

a tank is filled by a tap in 2 hour and outlet empty it in 4 hours if both the tapes are operated for 1 hour what will be the position of tank?​

Answer 1

Answer:

1/4

Step-by-step explanation:

given first tap fill the tank in 2 hrs

in one hour  first tap fill half tank

given second  tap empty the tank in 4 hrs

in our secod tank empty  1/4 tank

so 1 hour position of tank  =1/2-1/4 =1/4

Answer 2

Answer:

Step-by-step explanation:

           

          Tap 1              Tap 2 (negative work)

           2hrs                       4 hrs

Let's assume total work as 4 units (which is the LCM of 4 & 2)

Therefore, capacity of tap A & B would be

Tap A= 4/2= 2 units

Tap B = 4/4 = -1 units  (Capacity is in negative because of negative work)

Total capacity of A+B= 2-1 = 1 unit

Now if the taps are operated for 1 hour, the position of tank would be

=1/4