a tank is filled by one tap in 20 minutes and by another in 25 minutes. if both the taps are kept open for 5 minutes and then the second is turned off. in how many minutes the tank will completely filled ?
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Answered by
7
Answer:
Work done by both in 5 minute = (1/20 + 1/25) = 9/20
Remaining part = (1 - 9/20) = 11/20
Now, 1/20 part is filled in 1 minute. So, 11/20 part will be filled in 11 minute.
Hence, the tank will be full in 11 min
Answered by
1
Answer:
Solution
Work done by both in 5 minute = (1/20 + 1/25) = 9/20
Remaining part = (1 - 9/20) = 11/20
Now, 1/20 part is filled in 1 minute. So, 11/20 part will be filled in 11 minute.
Hence, the tank will be full in 11 min more
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