Question

A Tank is filled by three pipes with uniform flow . the first two pipes operating simultaneously in same time during third pipe line . second pipe fills the tank 5 hours than first pipe and 4 hours slower than the third pipe . the time required first pipe

Answer 1

Answer:

15hours

Step-by-step explanation:

Suppose, first pipe alone takes x hours to fill the tank.

Then, second and third pipes will take (x−5) and (x−9) hours respectively to fill the tank.

(2x−5)(x−9)=x(x−5)

⇒x2−18x+45=0

(x−15)(x−3)=0

⇒x=15. [neglecting x=3]