Math, asked by soumyadeepmah5814, 1 year ago

A tank is filled by two pipes p and q if he takes 2 hours more than q to fill the tank alone and p and q together fill the tank in 1 by 7 upon 8 hours then find the time taken by p and q alone to fill the tank

Answers

Answered by danielochich
13

Let;

Tap p takes = x hours

Rate = 1/x per hour

q takes = x-2 hours

Rate = 1/(x-2) per hour

When two work together;

Rate = 1/x + 1/(x-2)  per hour

        = (2x-2)/(x² -  2x)

Time taken to fill the tank = (x² -  2x)/(2x-2) = 1 7/8 = 15/8

 (x² -  2x)/(2x-2) = 15/8


8x²-46x+30=0

Solving for x

x = 5 or x = 3/4

We take x = 5

Therefore;

tap p takes 5 hrs

and 

tap q takes (5-2) = 3 hours

Attachments:
Answered by kshitij1237789
3

1

Secondary School Math 13 points

A tank is filled by two pipes p and q if he takes 2 hours more than q to fill the tank alone and p and q together fill the tank in 1 by 7 upon 8 hours then find the time taken by p and q alone to fill the tank

Ask for details Follow Report by Soumyadeepmah5814 03.06.2018

Answers

Me · Beginner

Know the answer? Add it here!

danielochich Ace

Let;

Tap p takes = x hours

Rate = 1/x per hour

q takes = x-2 hours

Rate = 1/(x-2) per hour

When two work together;

Rate = 1/x + 1/(x-2) per hour

= (2x-2)/(x² - 2x)

Time taken to fill the tank = (x² - 2x)/(2x-2) = 1 7/8 =

15/8

(x² - 2x)/(2x-2) = 15/8

8x²-46x+30=0

Solving for x

x = 5 or x = 3/4

We take x = 5

Therefore;

tap p takes 5 hrs

and

tap q takes (5-2) = 3 hours

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