Question

A tank is filled in 11 hours by three pipes a, b and


c. the pipe c is twice as fast as b and b is twice as fast as


a. how much time will pipe a alone take to fill the tank?

Answer 1

let time taken by a be x
then time taken by b is 2x
then time taken by c is 4x
acc to que
x+2x+4x=11
7x=11
x=7/11
time taken by a is 7/11 hrs

Answer 2

Answer:

Pipe a alone takes 77 hrs to fill the tank.

Step-by-step explanation:

Let time taken by pipe a= x hrs.

∴ Time taken by pipe b = x/2 hrs.

∴Time taken by pipe c = x/4 hrs.

Total time taken to fill the tank by 3 pipes= 11 hrs.

So,

(1/x) + (2/x) +(4/x) =1/11

(1+2+4)/x=1/11

7/x=1/11

   x=  11 ×7 =77 hrs